Resistance (R)
Resistance is property of a conductor to resist the flow of charges through it.
According to Ohm's Law, R = V / I
From this equation, we could say that Resistance (R) is inversely proportional to current (I) flowing through a resistor.
R α 1 / I ----- 1
I α 1 / R ----- 2
Here is a new formula for the Resistance (R):
Current (I) flowing through a wire decreases by one-half when the length of the wire (L) is doubled.
I α 1 / length of wire(L) ------ 3
Current (I) flowing through a wire is increased as thickness of the wire is increased for the same material and same length.
I α area of cross-section (A) ------ 4
Current (I) flowing through the wire is also dependent on the material of the wire.
From 3 and 4,
I α A / L ----- 5
From 5 and 2
I α 1/ R α A / L
Therefore,
1 / R α A / L
On cross multiplying,
R α L / A
Therefore, Resistance α Length of the wire / Area of cross section
To remove proportionality sign, we introduce a constant ρ (rho)
R = ( ρ L) / A ; ρ(rho) is a constant which differ based on the nature of material of the wire.
R = ( ρ L) / A ----- 6
According to Ohm's Law, R = V / I
From this equation, we could say that Resistance (R) is inversely proportional to current (I) flowing through a resistor.
R α 1 / I ----- 1
I α 1 / R ----- 2
Here is a new formula for the Resistance (R):
Current (I) flowing through a wire decreases by one-half when the length of the wire (L) is doubled.
I α 1 / length of wire(L) ------ 3
Current (I) flowing through a wire is increased as thickness of the wire is increased for the same material and same length.
I α area of cross-section (A) ------ 4
Current (I) flowing through the wire is also dependent on the material of the wire.
From 3 and 4,
I α A / L ----- 5
From 5 and 2
I α 1/ R α A / L
Therefore,
1 / R α A / L
On cross multiplying,
R α L / A
Therefore, Resistance α Length of the wire / Area of cross section
To remove proportionality sign, we introduce a constant ρ (rho)
R = ( ρ L) / A ; ρ(rho) is a constant which differ based on the nature of material of the wire.
R = ( ρ L) / A ----- 6