Problems related to Relative Density
In the previous post, we have dealt with Relative Density. Now, let us deal with some problem related to it.
Density of the substance A = 2 g/cm³
Relative Density of the substance A = Density of substance A/ Density of water at 4℃
Relative Density of the substance A = [2 g/cm³] /[1 g/cm³]
Relative Density of the substance A is 2, i.e., the density of the substance A is 2 times of the density of water(at 4℃ ).
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1. A box containing substance A of mass 0.008 kg. The volume it occupies is 4 cm³. Find the specific gravity[Relative Density] of the substance A ?
Given:
Mass of the substance A = 0.008 kg
Volume it occupied = 4 cm³
Density of the water at 4℃ is 1 g/cm³
To find:
Relative Density of the substance A
Solution:
We know that the mass of the substance is 0.008 kg, i.e., 8 g
The volume it occupies is 4 cm³.
Density of the substance A = Mass of the substance A / Volume it occupies
Density of the substance A = 8 g / 4 cm³Density of the substance A = Mass of the substance A / Volume it occupies
Density of the substance A = 2 g/cm³
Relative Density of the substance A = Density of substance A/ Density of water at 4℃
Relative Density of the substance A = [2 g/cm³] /[1 g/cm³]
Relative Density of the substance A is 2, i.e., the density of the substance A is 2 times of the density of water(at 4℃ ).
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2. Find the density of the Iron, given that the relative density of Iron is 8.5.
Relative Density of the substance = Density of substance / Density of water at 4℃
Relative Density of Iron = Density of Iron/ Density of water at 4℃
Density of Iron = Relative Density of Iron × Density of water at 4℃
Density of Iron = 8.5 × 1000 kg / m³
Density of Iron = 8500 kg/m³
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Density of Iron = Relative Density of Iron × Density of water at 4℃
Density of Iron = 8.5 × 1000 kg / m³
Density of Iron = 8500 kg/m³
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